Mayer's Formula is given by: Cp – Cv = R
But is the relation remains same for two mole of ideal gas, or is it
Cp - Cv = 2R
As, far as i know the number of moles are cancelled out in the derivation.
∆H = ∆U + nR∆T
nCp∆T = nCv∆T +nR∆T
Cp - Cv = R (remains same)
(∆H is enthalpy change, ∆U is internal energy change, n is no of moles, R is gas constant and ∆T is change in temperature, Cp is molar specific heat capacity of an ideal gas at constant pressure, Cv is molar specific heat capacity of an ideal gas at constant volume )