For an example if we take $\ce{KCl}$ and $\ce{NaCl}$ then I have understood the part where in aqueous state $\ce{Na+}$ becomes bigger than $\ce{K+}$ hence the conductivity reverses but in fused state ions exist on their own hence the conductivity order must remain $\ce{Na+} \gt \ce{K+}$
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$\begingroup$ Consider proper capitalization of chemical element symbols to be taken seriously. k is the Boltzmann constant. $\endgroup$– PoutnikJun 3, 2022 at 14:19
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2$\begingroup$ "Naked" $\ce{Na+}$ ions in melted salt, being smaller and more polarizing, may have bigger tendency to form ionic pairs with $\ce{Cl-}$, similarly as $\ce{Mg^2+(aq)}$ and SO4^2-(aq) have tendency to form ionic pairs is sea water as $\ce{MgSO4(aq)}$ $\endgroup$– PoutnikJun 3, 2022 at 14:26
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$\begingroup$ So basically in fused state as they are not solvated the ions having more effective nuclear charge(polarizing power) are able to interact more effectively with each other for an instance say Na+ and Cl- hence they reduce each others movement?? $\endgroup$– Mc'BrainzzJun 4, 2022 at 9:02
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$\begingroup$ Ionic pairs do not electromigrate. $\endgroup$– PoutnikJun 4, 2022 at 10:34
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$\begingroup$ could you please elaborate on that ? $\endgroup$– Mc'BrainzzJun 9, 2022 at 13:55
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