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For SN2 pathway we use an strong nucleophile (OH-,CN-) so they can easily substitute X(halogen) group from rear side.

While for elimination bimolecular reactions we use a strong conjugated base (RCH2O- or alc.kOH) so that it takes proton from carbon near by to halogen,thus forming an alkene .

While in my text book I had found enter image description here

I was agree with first diagram stating that bulky group will more tend to show elimination rather that substitution but in second diagram they show ethoxide ion giving substitution reaction .

To which I disagree, According to me it be should also show elimination reaction.

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  • $\begingroup$ Welcome to CH SE site! Note that using photos/screenshots of text instead of typing text itself is highly discouraged. The image text content cannot be indexed nor searched for, nor can be reused in answers. Specifically handwritten scripts can be difficult to decipher. Consider copy/pasting or rewriting of at least essential parts. Suitable formatting can be done according to formatting math/chem expressions/equations. $\endgroup$
    – Poutnik
    Commented May 10, 2022 at 7:16
  • $\begingroup$ @Poutnik I have issue with the diagram part of it . Text is only for giving context of what I'm talking about. $\endgroup$ Commented May 10, 2022 at 7:41
  • $\begingroup$ I see. It has looked for me like the essential part of the question. $\endgroup$
    – Poutnik
    Commented May 10, 2022 at 7:54
  • $\begingroup$ If would like to know what you take on this problem. $\endgroup$ Commented May 10, 2022 at 14:00
  • $\begingroup$ I would think you get a mixture of both, but I would be more biased towards the elimination than substitution. $\endgroup$
    – Zhe
    Commented May 10, 2022 at 14:04

1 Answer 1

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I think both elimination and substitution reaction will occur any of them can dominate cos ethoxide ion is a strong nucleophile and in presence of a alcohol as a solvent. So the reaction which will dominate depends upon solvent which is not mentioned. Moreover it is also a 2°alkyl halide so solvent is much more important factor.

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