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In the lecture our professor told us that nuclei with $S>1/2$ have a quadrupole and are therefore detected with NQR instead of NMR. The majority of all elements have nuclei with $S>1/2$.

I wondered why he used $S$ (electron spin) instead of $I$ (nuclear spin) in the slides?

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The nomenclature you mean has nothing to do with the electron spin S, it is something completely different. In heteronuclear experiments with two spins it is common to call them $I$ and $S$, with $I$ being the more sensitive nucleus. They're still both spin 1/2 nuclei.

$I$ is one spin, and $S$ is a different spin in this nomenclature, with a scalar coupling between them.

This nomenclature is usually introduced with the INEPT transfer and experiments like HSQC or HMQC.

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  • $\begingroup$ I don't think this is why the lecturer is using S instead of I. I think it is being used simply as an abbreviation for the term spin. Although I is the correct symbol for spin, a lot of NQR papers tend to refer to Spin-1 (or Spin-3/2 etc) nuclei. I think it is simply an extension of that terminology. $\endgroup$ – long Sep 18 '14 at 22:22
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Mad Scientist has provided a nice answer to your question about S and I. I'd like to comment on another aspect of your post.

our professor told us that nuclei with S>1/2 have a quadrupole and are therefore detected with NQR instead of NMR

"Instead of nmr" might be too strong. Most nuclei with a nuclear spin >1/2 can also be observed by nmr. Some of these nuclei may have a low relatively sensitivity to the nmr experiment, or due to nuclear quadrupole relaxation might produce signals where information has been lost, in which case NQR might be preferred. While there are many cases where the NQR experiment would be more informative than the NMR experiment, there are also many cases where NMR would work just fine.

An interesting example related to proton-nmr compares the following 3 compounds, pentadeuterioacetone, N-methylaniline and chloroform.

enter image description here

Deuterium, nitrogen and chlorine are quadrupolar nuclei. Deuterium and nitrogen-14 (the major isotope of nitrogen) both have a nuclear spin of 1, while chlorine-35 and -37 (the 2 predominant isotopes of chlorine) have a nuclear spin of 3/2. If one examines the proton-nmr of pentadeuterioacetone, one can observe the coupling between the deuterium and hydrogen nuclei. By the same token, if one examined the deuterium-nmr of this compound, one would observe the same H-D coupling. If one examines the proton-nmr of N-methylaniline, the coupling between nitrogen and the various protons is washed out, broadened signals where the coupling information has been lost are observed. In the case of chloroform, the proton-nmr shows only a sharp singlet.

Why the change in coupling to a proton as we change the coupled nucleus from D to N to Cl? The situation is very similar to physical exchange phenomena. If a proton is attached to a nucleus, then coupling can be observed between that proton and adjacent protons. If the proton is exchanging with the environment at a rate similar to the timescale of the nmr experiment, then the coupling will broaden. If the proton is exchanging very rapidly compared to the timescale of the nmr experiment, then the proton is effectively decoupled from the system and a sharp singlet will be observed.

In the case of the 3 compounds discussed above, instead of physical exchange, the proton is being relaxed (decoupled) at varying rates by the attached quadrupolar nuclei. The rate of quadrupolar relaxation caused by a coupled deuterium atom is slow on the nmr timescale, so all coupling is preserved and observed. The quadrupolar relaxation rate of nitrogen-14 is comparable to the timescale of the nmr experiment and so the coupling is beginning to wash out. The chlorine nuclei undergo rapid quadrupolar relaxation on the nmr timescale and are effectively decoupled from other nuclei.

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    $\begingroup$ "Instead of nmr" might be too strong. Utterly absurd actually. The principal advantage of NQR over NMR is that it can relies on energy level differences induced by electric fields, rather than magnetic fields. This makes it a far more portable technique, and is sometimes referred to as zero-field spectroscopy. It has some nice real-time applications (explosives detection, crude oil evaluation), but there is a clear lack of prominence in peer-reviewed literature compared to NMR studies of quadrupole nuclei. I wonder if said lecturer has a research interest in NQR spectroscopy..... $\endgroup$ – long Sep 18 '14 at 21:59
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I'd like to reply to "Mad Scientists" post: Now, because of your answers, I understand the topic better.

a) An electron can has a spin of s=1/2 (lower case s). The total spin quantum number S=1/2 (upper case S) is the sum of the single spins.

b) Although protons are nuclei, they are elementar particles (which have usually a spin of s=1/2). Protons have only a spin s=1/2 and therefor S=1/2.

c) In contrast to the mentioned two cases of elementar particles examples an atom (or ion with at least one electron; a proton is also an ion) have a spin quantum number s and a angular momentum quantum number l. So the two quantum numbers sum up to the nuclear spin which is usually determined by I= sum over all s + sum over all l. Very often we find as well instead of I the letter J = L + S in spectroscopy.

As "long" wrote, I belief also that the lecturer wrote S as an abreviation of Spin withouth distinguishing I und S.

If there is any thinking mistake don't hesitate to directly edit this post.

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