Here are four observations of the reactions of four metals

Question

Here are four observations of the reactions of four metals.

Metal F and G react slowly with water Metal H displaces metal G from its chloride salt solution Metal E does not react with dilute acids Metal H does NOT displace metal F from its sulphate salt solution.

What is their order of reactivity, starting from the most reactive metal to the least reactive metal?

F>H>G>E; H>G>F>E; H>E>F>G; G>H>F>E; None of these

I'm really unsure how to order them I would say F>H>G>E but thats half guessing. Can someone give me a clue to arrange them right?

Answer 1

Before starting of with my reasoning , I must tell you that your answer ( whether guessed or logically reasoned ) looks correct according to me .

I am assuming that you are familiar with the Metal Reactivity Series ( if not look here )

We shall take use of a well presented reactivity series :

_{(source: wikispaces.com)}

Now to crack the answer clue by clue :

1.

Metal F and G react slowly with water.

Hence F and G are somewhere at the top.

2.

Metal H displaces metal G from its chloride salt solution

Clearly H>G.

3.

Metal E does not react with dilute acids

E will come somewhere at the bottom half so F,G>E (from 1) and we can further say H>G>E (from 2)

4.

Metal H does NOT displace metal F from its sulphate salt solution

This gives F>H.

Combine last two clues' result to get F>H>G>E .