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Well, according to the proton-electron ratio $\ce{O-}$ should be bigger than $\ce{F-}$

What about the charge/electron density in $\ce{F}$? Will it not affect the size of the atom of $\ce{F-}$?

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  • $\begingroup$ I think $\ce{O-}$ is the bigger guy. Since $\ce{F-}$ have a complete octet and also have more protons than $\ce{O-}$. $\endgroup$
    – ashu
    Commented Sep 7, 2014 at 15:35
  • $\begingroup$ @Siddharth Yadav, What about the charge/electron density in O? $\endgroup$
    – EJC
    Commented Sep 7, 2014 at 18:46

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definitely $\ce{O-}$

In $\ce{O-}$ 7 outer electrons are tied to nuclei with 6 positive charges (number 8 minus 2 electons of inner shell), while in $\ce{F-}$ 8 outer electrons are tied to nuclei with 7 charges. The difference, however, should be quite small.

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