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the reaction Gibbs energy of a cell:

$\Delta_rG^o=-nFE^o$

and the Gibbs energy of photoinduced electron transfer:

$\Delta_{ET}G^o=N_A\{e[E^o(D^{+.}/D)-E^o(A/A^{-.})]+\omega(D^{+.}A^{-.})-\omega(DA)\}-\Delta{}E_{0,0}$

(https://goldbook.iupac.org/terms/view/GT07388).

Are both the same except for the vibrational zero electronic energy of the excited partner $\Delta{}E_{0,0}/Jmol^{-1}$ (energy of the excited state)?

The Gibbs energy of photoinduced electron transfer accounts for the effect of Coulombic attraction in the products, $\omega(D^{+.}A^{-.})$; and reactants, $\omega(DA)$. Why does the reaction Gibbs energy of a cell not have these terms?

Thank you.

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