In this diagram optical isomers has divided in to 2 categories, one is diastereomers and enantiomers. Is the example for diastereomers correct? For me its looks like enantiomers
$\begingroup$ What do you think? $\endgroup$– user55119Nov 27, 2021 at 3:21
$\begingroup$ Are the carbons bearing the Br the same?. What about the carbons bearing Cl? $\endgroup$– user55119Nov 27, 2021 at 3:27
I'm not sure why you think they are enantiomers. They are actuallually diastereomers as stated:
As depicted, the compound to the left is $(2R,3S)$- while the compound to the right is $(2R,3R)$-. Thus, they are pair of diastereomers.
To be enantiomers, either the compound to the left should be $(2S,3S)$- or the compound to the right should be $(2S,3R)$-.