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According to the Handbook of Inorganic Chemicals by Pradyot Patnaik, Ph.D. 2003, $\ce{SbCl5}$ reacts with $\ce{I2}$ to form $\ce{ICl}$ (Iodine monochloride). So far I got, $\ce{SbCl5 + I2 -> ICl + SbCl3}$, where $\ce{SbCl5}$ is the oxidizing agent and the $\ce{I2}$ is the reducing agent. Is this right?

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    $\begingroup$ If you do not even try, do not expect others to help. $\endgroup$
    – Poutnik
    Nov 24 at 22:01
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    $\begingroup$ Clarify what is going to be oxidized, and what is going to be reduced. Balance these equations. Then join the information. $\endgroup$
    – Buttonwood
    Nov 24 at 22:04
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    $\begingroup$ If the book tells you that it reacts, but then doesn't tell you how it reacts, how good can the book be? $\endgroup$ Nov 24 at 22:21
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    $\begingroup$ On Chemistry mathematical and chemical expressions can be formatted using MathJax (and LaTeX Syntax). If you want to know more, please have a look here and here. We prefer to not use MathJax in the title field, see here for details. $\endgroup$ Nov 24 at 23:46