These are the two enolic forms that I could make. So according to me, the total number of distinct enol forms of acetylacetone is $2$. But the answer is 3, what am I missing?
I have drawn the enols and keto forms of acetyl acetone . The ones with equality are the same structure just flipped along the line I have shown on right . I don't see how your first structure had a chiral carbon atom because the carbon you marked is bonded to two hydrogen atom . Regardless I am also getting 3 stable forms . One could say we would have another pair of enantiomers of cummulated alkene . But that is generally not considered stable . So I didn't include that .