I was asked the following question in my introductory chemistry class:
The diameter of metal wire is often referred to by its American wire gauge number. A 16-gauge wire has a diameter of $\pu{0.05082 in}$. What length of wire, in meters, is there in a $\pu{1.00 lb}$ spool of 16-gauge copper wire? The density of copper is $\pu{8.92 g/cm^3}$.
First I converted the imperial measurements to metric. $\pu{0.05082 in} = \pu{0.12908 cm}$, $\pu{1 lb} = \pu{0.45359 kg}$, according to Google. So I can use $\pi r^2 h$ to calculate the volume (and thus, using density, calculate the mass) of one meter of wire, I figure the radius to be $\pu{0.06454 cm}$. The equation becomes $V = \pi \times (\pu{0.06454 cm})^2 \cdot \pu{100 cm}$, which equals $\pu{0.41654 cm^3}$. So that's the volume of one meter of wire.
Using the density of copper $(\pu{8.92 g/cm^3})$, I figure the mass of one meter of wire to be $\pu{3.72 g}$. If $\pu{1 lb} = \pu{453.59 g}$, then converting $\pu{3.72 g}$ to lbs gives me $\pu{3.72 g} \cdot \frac{\pu{1 lb}}{\pu{453.59 g}} = \pu{0.01 lbs}$. So assuming I did everything correct, one meter of wire is a hundredth of a pound, so in one pound of wire there is $100$ meters.