Question:
Classify each of the following ions according to whether they react with water to give a neutral, acidic, or basic solution:
As a general rule:
Strong acid + Strong base $\rightarrow$ Neutral solution
Strong acid + weak base $\rightarrow$ acidic solution
Weak acid + Strong base $\rightarrow$ Basic solution
According to my solutions manual.
a) $\ce{F-}$ is the conjugate base of a weak acid, therefore the solution is basic.
b) $\ce{Br-}$ is the anion of strong acid, therefore the solution is neutral.
c) $\ce{NH4+}$ is the conjugate acid of a weak base, therefore the solution is acidic
d) $\ce{[K(H2O)6]+}$ is the conjugate base of a weak acid, therefore the soltuion is basic.
e) $\ce{SO3^2-}$ is the conjugate base of a weak acid, therefore the solution is basic
f) $\ce{[Cr(H2O)6]^3+}$ is an acidic solution, therefore the solution is acidic.
However, all these answers imply that water is acting as a strong base. How is this possible when water pH is $\sim 7$?