The problem is, we want to see a trend in everything. There are various factors that govern melting point and boiling point which is the reason of perceived anomalies. "The equation which has more number of variables, is harder to solve."
For melting point, few of them are: Crystal system, size of atom, atom-atom distance, distance between two layers of atoms, metallic character, metallic bond strength, inert pair effect, relativistic effect, etc.
Note that, down a group, metal-metal bond strength decreases due to increase in size but metallic character increases because now, $\ce{e-}$ abstraction is easy from that metal.
Group 1 and 2: All have metal-metal bond but the strength of bond decreases. Thus, m.p. decreases.
Group 13: Except $\ce{B}$ all are metals. The m.p. decreases from $\ce{B}$ to $\ce{Al}$ then decreases for $\ce{Ga}$ and then increases till $\ce{Tl}$.
The low m.p. of $\ce{Ga}$ is due to existance of $\ce{Ga2}$ dimers in the orthorhombic crystal. The higher m.p. of $\ce{In}$ and $\ce{Tl}$ may be due to body centered tetragonal and hexagonal close packing structures, respectively.
This explains the boiling point trend in group 13.
Group 14: Except $\ce{C}$, $\ce{Si}$ and $\ce{Ge}$, all ($\ce{Sn}$ and $\ce{Pb}$) are metal. The m.p. decreases till $\ce{Sn}$ and then increases for $\ce{Pb}$.
$\ce{Ge}$ has face centered diamond cubic lattice, $\beta~\ce{Sn}$ has body centered tetragonal lattice and $\ce{Pb}$ has face centered cubic lattice. The higher m.p. of $\ce{Pb}$ than that of $\ce{Sn}$ may be due to this factor and a lower van der Waals radius.
In group 15 the melting/boiling point increases up to Arsenic and then started decreasing.
Group 15: The m.p. increases upto $\ce{Sb}$ then $\ce{Bi}$ has a low melting point. $\ce{As}$ sublimes at $\pu{887 K}$ and $\pu{1 atm}$.
$\ce{As}$, $\ce{Sb}$ and $\ce{Bi}$ all have layered structure crystalising in rhombohedral lattice. The atomic radius of $\ce{Sb}$ and $\ce{Bi}$ are very similar. The low m.p. may be due to higher atom-atom and layer-layer distance than those in $\ce{Sb}$ as explained here.
Group 16: The m.p. increases upto $\ce{Te}$ then $\ce{Po}$ has a low melting point.
$\ce{S}$ is orthorhombic, grey $\ce{Se}$ is hexagonal, $\ce{Te}$ is rhombohedral and $\alpha~\ce{Po}$ is simple cubic.
Another reason for low m.p. and b.p. of $\ce{Po}$ is explained here.
Group 17 and 18: None of them are metals. The m.p. and b.p. increases uniformly with the increase of van der Waals forces.
I know that this is not a complete answer but you can do your own findings based on this.