# Reduction of conjugated ketone with lithium aluminium hydride

I came across a question about reduction of a conjugated ketone with $$\ce{LiAlH4}$$. Although it seemed quite easy at first sight, everything became cloudy as I dug deeper. My doubts regarding the question are:

1. I have heard that conjugated double bonds are reduced by $$\ce{LiAlH4}$$. Is there any chance that the Oxygen from the ether group takes part in conjugation?
2. If not, why?
3. Is there a chance that the ether is cleaved during the acidic workup?
4. What is the true mechanism of this reaction, and does it involve the following intermediate? Please help me with this question. Thanks in advance.
• The reagents should read 1) LiAlH4, 2) H3O+. After step 1), "d" is the product. After hydrolysis, "a" is formed. Aug 12, 2021 at 18:54
• You might be interested in this: chemistry.stackexchange.com/questions/87138/… Aug 12, 2021 at 19:01
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