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I came across a website that said it is possible for sodium hydroxide to react with manganese dioxide at temperatures near 0 degrees Celsius. The reaction goes: 2MnO2 + 3NaOH ⇄ MnO(OH) + Na3MnO4 + H2O [

Source: https://chemiday.com/en/reaction/3-1-0-7458 Is this actually a feasible reaction and if so how would one tilt the equilibrium to the right?

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    $\begingroup$ Chemiday is not a reliable source. This time, however, they copypasted this reaction from the Russian textbook Lidin, V. A. Molochko, and L. L. Andreeva, Reactivity of Inorganic Substances, 3rd ed.; Khimia: Moscow, 2000, p. 397. How do I know? They didn't bother with proper chemical names and transcribed Russian spelling ("gipomanganate"). Don't use that website. As for the question, the answer is evident if you apply Le Chatelier's principle (hint: temperature aside, $\ce{MnO(OH)}$ is precipitate). $\endgroup$
    – andselisk
    Jul 16 at 22:11
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    $\begingroup$ Please visit this page, this page and this one on how to format your posts better with MathJax and Markdown. $\endgroup$
    – andselisk
    Jul 16 at 22:12