Sodium hydroxide reaction with manganese dioxide [duplicate]

I came across a website that said it is possible for sodium hydroxide to react with manganese dioxide at temperatures near 0 degrees Celsius. The reaction goes: 2MnO2 + 3NaOH ⇄ MnO(OH) + Na3MnO4 + H2O [

Source: https://chemiday.com/en/reaction/3-1-0-7458 Is this actually a feasible reaction and if so how would one tilt the equilibrium to the right?

• Chemiday is not a reliable source. This time, however, they copypasted this reaction from the Russian textbook Lidin, V. A. Molochko, and L. L. Andreeva, Reactivity of Inorganic Substances, 3rd ed.; Khimia: Moscow, 2000, p. 397. How do I know? They didn't bother with proper chemical names and transcribed Russian spelling ("gipomanganate"). Don't use that website. As for the question, the answer is evident if you apply Le Chatelier's principle (hint: temperature aside, $\ce{MnO(OH)}$ is precipitate). Jul 16 at 22:11