First, the alloy $(0.5$ to $\pu{2 g})$ should be treated by $\pu{10 mL}$ nitric acid $32\,\%.$ All metals will get dissolved, except tin and silicon, which will be transformed into insoluble dioxide $\ce{SnO2}$ or $\ce{SiO2}$. Dilute in $\pu{100 mL}$ hot water. $\ce{SiO2 + SnO2}$ will make a gelatinous precipitate, that can be eliminated by filtration. Add $\pu{0.2 g}~\ce{Na2SO4}$ and $\pu{0.2 g}~\ce{NaCl}$ in order to remove lead and silver: lead sulfate $\ce{PbSO4}$ and silver chloride $\ce{AgCl}$ will precipitate, and are eliminated by filtration.
The remaining solution contains aluminum, copper and nickel. If you want to separate copper, you may add $\pu{2 g}$ potassium iodide $\ce{KI},$ that will make a precipitate of copper(I) iodide $\ce{CuI}$ according to the reaction
$$\ce{2 Cu^2+ + 5 I^- -> 2 CuI(s) + I3^-}\tag{1}$$
So copper may be separated as a white precipitate ($\ce{CuI}$). This reaction is specific. In the final solution, nickel can be separated with dimethylglyoxime. Add $\pu{10 mL}$ of a dimethylglyoxime $(\ce{C4H8N2O2})$ solution $(1\,\%$ in ethanol). Add slowly some ammonia $\pu{2 M}$ up to the $\mathrm{pH}$ is just greater than $7$. An intense red precipitate of nickel dimethylglyoxime $\ce{Ni[C4H5N2O2]}2$ appears and can be filtrated:
$$\ce{2 C4H8N2O2 + Ni^2+ -> Ni(C4H7N2O2)2 + 2 H^+}\tag{2}$$
This reaction is specific, and the other metals do not interfere.