# Can nitric oxide(NO) reduce Xenon Fluorides

I came across the following question:

$$\ce{XeF_4}$$ on reaction with gaseous nitric oxide forms Xenon gas and (P).Find the total number of lone pairs present in one molecule of P.

As far as Xenon chemistry is concerned, I just know that Xenon Fluorides undergo hydrolysis giving different products like Xe,$$\ce{XeOF_4 ,XeO_2F_2 ,XeO_3}$$.
I have no idea that Xenon Fluorides even react with nitric oxide.
I did a lot of digging on Google but could not find a single source/article discussing about the reaction of Xenon Fluorides with nitric oxide or the other way round.
I would be glad if someone can tell about the products of the given reaction with a link to the source.
The answer is given as '6 lone pairs'.

The rate of reaction of $$\ce{XeF4}$$ and $$\ce{XeF2}$$ with $$\ce{NO}$$ and with $$\ce{NO2}$$ has been studied between $$\pu{300° - 350°K}$$ at pressures between $$\pu{0.1 - 30 mm}$$. The second‐order rate constant at $$\pu{300°K}$$ and the activation energies are, respectively: $$\ce{XeF4 + NO}$$, ($$\pu{3 liters/mole sec, 7 kcal/mole}$$); $$\ce{XeF2 + NO}$$, ($$\pu{0.3 liters/mole sec, 10 kcal/mole}$$). The rate of $$\ce{NO2}$$ with $$\ce{XeF4}$$ and $$\ce{XeF2}$$ was too slow to observe, $$\pu{k < 0.01 liter/mole sec}$$. The fluorides of xenon react with the oxides of nitrogen much more slowly than $$\ce{F2}$$ reacts with $$\ce{NO}$$ or $$\ce{NO2}$$. By means of a Polanyi—Semenov plot, the reactions of $$\ce{XeF4, XeF2}$$, and $$\ce{F2}$$ with oxides of nitrogen were combined to give an estimate of the successive dissociation energies of $$\ce{XeF4}$$, which are (kcal/mole): $$\ce{XeF4→XeF3 + F (48)}$$; $$\ce{XeF3→XeF2 + F (15)}$$; $$\ce{XeF2→XeF + F (54)}$$; $$\ce{XeF→Xe + F (11)}$$. From these kinetic and thermochemical data a strong case can be made for the stepwise reduction of $$\ce{XeF4}$$.
• @ Nilay Ghosh. So basically the Fluorine atoms react to form $F_2$, which has 6 lone pairs. Thanks a lot. Jul 10 at 9:34