# Reaction of alkyl halides with strong unhindered bases

For (b) and (c), what the solution manual says makes no sense to me. You're reacting a primary alkyl halide with an unhindered base $$\ce{EtONa}$$. They say that the only product is the alkene. Why do they not consider the $$\mathrm{S_N2}$$ reaction that WILL take place in larger quantity? I'm uploading the question too on the other website

I agree with you, I'd expect some $$\mathrm{S_N2}$$ product too. I'm not sure about the relative quantities of the $$\mathrm{E2}$$ and $$\mathrm{S_N2}$$ products though.
I wouldn't flat out say that you'd expect more $$\mathrm{S_N2}$$ product than $$\mathrm{E2}$$ product, because although the substrate is unhindered, the solvent is ethanol, which is protic. The solvent interacts with the nucleophile through hydrogen bonding.
This hinders the nucleophile. This slows down the rate of the $$\mathrm{S_N2}$$ reaction because now the nucleophile is dragging along lots of solvent molecules, and it also increases the bulk of the nucleophile.