How to write the steady state for $\ce{A}?$ $$\ce{A ->[$k_1$] B ->[$k_2$] C ->[$k_3$] A}$$

Species $\ce{A}$ seems to appear on both side of equation as it uses itself to produce some of itself. I have checked some online tutorials but I found none cover this scenario.

  • $\begingroup$ One approximation could be $\ce{B <=> C}$ and at steady state, $\ce{[B]}$ and $\ce{[C]}$ do not change. $\endgroup$ May 24 '21 at 18:41
  • 2
    $\begingroup$ A, B and C remain constant in this scheme. $\endgroup$
    – Maurice
    May 24 '21 at 18:46
  • 1
    $\begingroup$ They come to equilibrium with amounts proportional to the ratio of rate constants. If all k's are equal then the population is 1/3 each. $\endgroup$
    – porphyrin
    May 25 '21 at 10:05
  • 1
    $\begingroup$ Related. $\endgroup$ May 25 '21 at 11:58

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