In my textbook, it is written that lowering of vapour pressure is not a colligative property but relative lowering of vapour pressure is a colligative property. But why is that? There is literally no explanation given in my textbook as to why this is true. Please someone explain. I am so confused. Please help. (By lowering of vapour pressure I mean $P_{0} - P_{S}$ where $P_{0}$ is the vapour pressure of pure solvent and $P_{S}$ is the vapour pressure of the solvent containing non-volative solute. Relative Lowering in Vapour Pressure means $\frac{P_{0} - P_{S}}{P_{0}}$).
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$\begingroup$ Could you clarify with respect to the difference between 'relative lowering' and 'lowering'? $\endgroup$– Jon CusterMay 6, 2021 at 18:27
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4$\begingroup$ Consider reporting the whole sentences $\endgroup$– AlchimistaMay 7, 2021 at 9:10
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1$\begingroup$ Yeah, like @Alchimista said, please give us the complete quote; plus please include a full citation to the textbook (author, name, publication year, publisher, edition, etc.). $\endgroup$– theoristJun 23, 2021 at 4:23
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$\begingroup$ Both 'lowering of vapour pressure' and 'relative lowering of vapour pressure' are colligative properties. $\endgroup$– Silica19Aug 3, 2022 at 13:09
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$\begingroup$ In my textbook of Maharashtra state board it is mentioned that both lowering in vapor pressure and rative lowering in vap pressure are colligative properties. $\endgroup$– user130590Jan 18 at 5:20
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1 Answer
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A colligative property is a property which depends on number of solute particles and not on nature of solute particles. Relative lowering in vapour pressure is equal to the mole fraction of the solute . This can be derived using $P_s=P_0\cdot x_\text{solvent}$ where $x$ is the mole fraction and Po is the vapour pressure of pure solvent. Lowering of vapour pressure is also a colligative property as it is equal to $\frac{x_\text{solute}}{P_0}$. $P_0$ is a property of the solvent, not the solute.
