I am running an electrolysis between two silver electrodes. The “electrolyte” is deionized water. Ions are still formed as the CO2 of the air generates enough ions for a few µA of current. During the electrolysis the ions are converted to metallic silver nanoparticles due to strong ultraviolet radiation.

I have the following variables:

  1. Current in Ampere [A]
  2. Time passed in seconds [s]
  3. Coulomb [C or As]
  4. Quantity of deionized water [l (liter)] I want to know:
  5. On the anode dissolved silver in milligrams [mg]
  6. PPM of silver in the deionized water [PPM]

In practice there will be some silver ions that make it from the anode to the cathode without “colliding” with an photon – so they will be depleted on the cathode. However for the calculation I assume that all ions will get reduced to metallic nanoparticles and nothing will be depleted on the cathode.

How do I calculate the dissolved silver in mg and the PPM of the solution?

Thanks in advance!

  • $\begingroup$ Note that "ppm" is an ambiguous way to describe concentration and its usage is discouraged. See, for example, my answer. $\endgroup$
    – andselisk
    Commented Apr 2, 2021 at 11:47
  • 1
    $\begingroup$ First no electrolysis can be made in deionized water. What voltage ? Under high tension, an ark may be obtained. Is it what you want ? Then you speak of ultraviolet radiation. Why ? Where ? Why don't you add silver nitrate in the solution ? Finally what are you trying to do ? $\endgroup$
    – Maurice
    Commented Apr 2, 2021 at 11:51


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