I am running an electrolysis between two silver electrodes. The “electrolyte” is deionized water. Ions are still formed as the CO2 of the air generates enough ions for a few µA of current. During the electrolysis the ions are converted to metallic silver nanoparticles due to strong ultraviolet radiation.

I have the following variables:

  1. Current in Ampere [A]
  2. Time passed in seconds [s]
  3. Coulomb [C or As]
  4. Quantity of deionized water [l (liter)] I want to know:
  5. On the anode dissolved silver in milligrams [mg]
  6. PPM of silver in the deionized water [PPM]

In practice there will be some silver ions that make it from the anode to the cathode without “colliding” with an photon – so they will be depleted on the cathode. However for the calculation I assume that all ions will get reduced to metallic nanoparticles and nothing will be depleted on the cathode.

How do I calculate the dissolved silver in mg and the PPM of the solution?

Thanks in advance!

  • $\begingroup$ Note that "ppm" is an ambiguous way to describe concentration and its usage is discouraged. See, for example, my answer. $\endgroup$
    – andselisk
    Apr 2, 2021 at 11:47
  • 1
    $\begingroup$ First no electrolysis can be made in deionized water. What voltage ? Under high tension, an ark may be obtained. Is it what you want ? Then you speak of ultraviolet radiation. Why ? Where ? Why don't you add silver nitrate in the solution ? Finally what are you trying to do ? $\endgroup$
    – Maurice
    Apr 2, 2021 at 11:51


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Browse other questions tagged or ask your own question.