# Why Inorganic chemistry reaction mechanisms are hard to find?

My textbook Chemistry Part 1,as in the attached photo states that[after the KClO3 reaction] “This reaction which apparently seems to be of the tenth order is actually a second order reaction. This shows that it takes place in several steps.” If that is so, then as stated above it, all higher order inorganic chemistry reactions must have some sort of mechanism. But it is really hard to find the mechanisms(many a times one cannot find them). Why is that so??.

• I think the relative lack of molecular structure plays a role, too. Mar 26 at 10:34
• @Alchimista But even for those whose molecular structures are known the reaction mechanisms are unheard of those as well. Mar 26 at 11:32
• @Rishi well sure see answer. Which is related. We deal with billiard collisions, in a sketchy way. Mar 26 at 11:36
• Mar 26 at 20:43
• Does this answer your question? Inorganic chemistry reaction mechanisms Apr 7 at 10:29

Reactions can be of order $$0, 1 , 2$$ or $$3$$ , but never more. No collision may happen between more than three particules simultaneously. If an equation is written with more than $$4$$ substances on the lefthand side, it means that the corresponding reaction is a sum of several elementary reactions.
Mechanisms in inorganic reactions are hard to establish because they are made of a lot of successive reactions, in cascade. And each step is so quick that it cannot be studied. For example your oxidation of $$\ce{Fe^{2+}}$$ ion by $$\ce{KClO3}$$ is probably a series of at least $$6$$ steps which are all nearly instantaneous : To be able to study such a mechanism, the $$6$$ intermediate states must be observed for at least some nanoseconds. If the intermediate states are too short living, all we can do then is to make hypothesis without experimental arguments.