I want to know if the structure I drew is sucrose or an enantiomer of it.

The One I Made:
The one I made

The one on internet:
The one on internet


Those are the same molecules - the fructose part has just been rotated about the glycosidic bond (the oxygen between the two).

Enantiomers are molecules that have the same formula, but are non-superimposable - there have to be differences in chirality. If you can superimpose the structures by rotating about a bond or by rotating the molecule, it is not an enantiomer.

  • $\begingroup$ Aha! you mean rotating the fructose ring on a horizontal axis by $180^o$, I didn't notice that... $\endgroup$
    – RE60K
    Jul 31 '14 at 13:58
  • $\begingroup$ I agree that the drawn structure is sucrose $\endgroup$
    – Tony M
    Sep 21 '19 at 12:44

Not the answer you're looking for? Browse other questions tagged or ask your own question.