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I want to know if the structure I drew is sucrose or an enantiomer of it.

The One I Made:
The one I made


The one on internet:
The one on internet

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1 Answer 1

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Those are the same molecules - the fructose part has just been rotated about the glycosidic bond (the oxygen between the two).

Enantiomers are molecules that have the same formula, but are non-superimposable - there have to be differences in chirality. If you can superimpose the structures by rotating about a bond or by rotating the molecule, it is not an enantiomer.

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  • $\begingroup$ Aha! you mean rotating the fructose ring on a horizontal axis by $180^o$, I didn't notice that... $\endgroup$
    – RE60K
    Jul 31, 2014 at 13:58
  • $\begingroup$ I agree that the drawn structure is sucrose $\endgroup$
    – Tony M
    Sep 21, 2019 at 12:44

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