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I am having trouble in this question:

Structure of H₂S₂O₈ Hydrolysis of one mole of peroxy disulphuric acid with one mole of water produces :

  • a)two moles of sulphuric acid only
  • b)two moles of peroxymonosulphuric acid
  • c)one mole of sulphuric acid and one mole of peroxy monosulphuric acid
  • d)one mole of sulphuric acid, one mole of peroxymonosulphuric acid and one mole of hydrogen peroxide

when hydrolyzing H₂S₂O₈ cleaving the S-OH linkage and S=O is of no use since it returns the same compound and peroxide linkage is non-polar hence can't be cleaved. So only S-O linkage should be cleaved that would result in the formation of 1 mole of H₂O₂ and 2 moles of H₂SO₄. But that doesn't match to any of the options. Can someone please explain me how to solve it?

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    $\begingroup$ The problem specifies a 1:1 ratio of peroxy disulfuric acid to water. So what do you get if you cleave one S-O linkage? $\endgroup$ – Waylander Mar 10 at 13:43
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Without speaking of mechanism, here is an explanation valid for the average high school students, not specially inclined to chemistry. Suppose the bond $\ce{O-O}$ is broken, producing two identical radicals $\ce{HSO4·}$. Suppose one mole of $\ce{H2O}$ is also broken into $\ce{H}$ and $\ce{OH}$. Then, $\ce{H}$ gets attached to the first radical, and $\ce{OH}$ to the second. It produces one mole sulfuric acid and one mole peroxymonosulfuric acid.

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