# Net direction of dipole moment in oxygen difluoride

What is the net direction of dipole moment in $$\ce{F2O}$$ molecule?

In the case of $$\ce{NH3}$$ and $$\ce{NF3}$$ molecules both have net dipole moment with direction reversed due to strong electronegativity of fluorine atoms, whereas in the case of $$\ce{H2O}$$ the direction of net dipole moment is from oxygen atom towards lone pair with a value $$\mu(\ce{H_2O}) = \pu{1.84 D}.$$

But in my textbook the value of net dipole moment of $$\ce{F_2O}$$ molecule is given $$(\mu(\ce{F2O}) = \pu{0.3 D}),$$ but not its direction. I have done a lot of research on google but I could not find any related information.

After going through a standard book on inorganic chemistry , I found the answer. The direction of dipole moment in $$F_2O$$ is just reversed as in the case of $$NF_3$$ i.e from oxygen atom towards fluorine atoms. Reference: Concise Inorganic Chemistry 5th edition by J.D.LEE; Chapter "CHEMICAL BONDING" topic "APPLICATION OF DIPOLE MOMENT".