# Molecular geometry of BaH2 according to VSEPR theory

I am asked to predict the correct molecular geometry of $$\ce{BaH2}$$ according to VSEPR theory. I assumed that it is linear due to barium being an alkaline earth metal and therefore not having any lone pairs when bonded to two hydrogen atoms, but apparently the bond angle between the two hydrogen atoms is about 119°. Why is that the case and how can one explain this observation with VSEPR theory?

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• Your logic is correct. VSEPR fails to predict the correct structure of BaH2. See pubs.acs.org/doi/10.1021/acs.jpca.9b10248 Mar 5 '21 at 21:42
• isnt BaH2 ionic? does VSEPR applies to ionic compounds? Mar 6 '21 at 4:50