I've read some answers online but I still can't seem to understand the mirror image effect. Why is the highest energy absorption (v" = 0 to v' = 4) the lowest energy fluorescence (v' = 4 to v" = 0)? Shouldn't the molecule that absorbs the highest-energy light emit the highest-energy light?

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    $\begingroup$ Please look at Jablonski diagram and, in particular, the second figure shown there. Then follow the links for Stokes shift and Kasha’s rule. $\endgroup$ – Ed V Feb 26 at 2:31
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    $\begingroup$ See the answer here chemistry.stackexchange.com/questions/134675/… $\endgroup$ – porphyrin Feb 26 at 9:04
  • $\begingroup$ @porphyrin Thanks for the help, I still don't understand why the highest energy absorption would have the lowest energy fluorescence. Am I missing something here? $\endgroup$ – Mark Feb 26 at 17:52

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