After this cyclic ether is activated with H+, will the bromide attack the more substituted site on the left or the less substituted side on the right? I think it will attack the right because SN2 favors less steric hindrance, but what is confusing me is that for acid activated epoxides, nucleotides attack the more substituted site. Can anyone clarify this for me? Does it have to do with the size of the ring? The charge of the nucleophile? Please help.