I am trying to figure out the NMR spectra of F3P-BH3
I am solving this out using 2nI+1 rule.
IP = 1/2 and IB = 3/2
Hence for this compound,
(2nIP+1)(2nIB+1) = (2x1X1/2+1)(2X1X3/2+1) = (2)(4) = 8 lines (quadraplet of doublet)
This is what I came up with, it would be great if you could correct me if I'm wrong. Trying to solve few problems before the exam =)