# How is the central carbon in 3‐bromopentane‐2,4‐diol chiral?

My teacher told us the middle carbon in 3‐bromopentane‐2,4‐diol is chiral:

$$\ce{CH3-CH(OH)-\overset{\star}{C}H(Br)-CH(OH)-CH3}$$

Since there are two identical groups around it, I would guess it should not be chiral.

It was a pre-recorded class and I was not able ask this question. Has my teacher made a mistake?

• Rotational symmetry isn't related to chirality. To be more precise, the lack of improper rotations $S_n$ is associated with chirality; but proper rotations $C_n$ have no relation to chirality. PS sorry about the edits. I need to double check this. – orthocresol Jan 20 at 19:00