# Transition metals with closed shells

From wiki page about valence electrons:

An atom with a closed shell of valence electrons (corresponding to an electron configuration $$s^2p^6$$ for main group elements or $$d^{10}s^2p^6$$ for transition metals) tends to be chemically inert.

My question is, which are the transition metals with $$d^{10}s^2p^6$$? Looking at the periodic table, I do not see anyone.

After this paragraph, wiki says that valence orbitals for d-block elements (transition metals) are (see table):

ns (n-1)d np

I though one of the characteristics of transition metals is that they do not have electrons in last p orbital.

(1) It isn't possible to have a transition metal that has the electronic structure $$\mathrm{(n-1)d^{10} ns^2np^6}$$. Such an electronic structure would imply a noble gas.

(2) Gold $$\mathrm{[Xe]4f^{14} 5d^{10} 6s^1}$$ and platinum $$\mathrm{[Xe]4f^{14} 5d^{9} 6s^1}$$ are the most noble metals and neither even has a $$\mathrm{(n-1)d^{10} ns^2}$$ configuration.

Granted these configurations are for the free atom, not the bulk metal...

• I'm sorry, but I do not understand this answer. You cite a phrase not in the question nor in the wiki page, where is it from ? Moreover, answer starts by "your premise". About what premise are you talking ? – pasaba por aqui Jan 13 at 9:50
• @pasabaporaqui - I tried to clarify the answer. I'm not sure what you meant by You cite a phrase not in the question nor in the wiki page, where is it from ? – MaxW Jan 13 at 16:54
• Thanks. At least in my computer, the phrase "Granted these configurations ..." appears as a citation (gray bar at left). But I do not see the source of this cite. – pasaba por aqui Jan 13 at 19:07
• @pasabaporaqui - the phrase "Granted these configurations ..." is from my own knowledge, not a quote. I don't understand your confusion. Atoms in a bulk metal are bonded together, they are not free atoms. – MaxW Jan 13 at 20:27

The zinc atom $$\ce{Zn}$$ has the configuration $$\ce{(Ar) 3d^{10} 4s^2}$$ or, if you prefer : $$\ce{1s^2 2s^2 2p^6 3s^2 3p^6 3d^{10} 4s^2 }$$. The same final configuration is repeated with the cadmium atom $$\ce{Cd}$$, and with the mercury atom $$\ce{Hg}$$. Is it not what you are looking for ?

• Zinc does not seem to be inert ... . – Oscar Lanzi Jan 12 at 22:01
• @Oscar Lanzi. I agree. Of course zinc is not inert. But the question was not about the element to be inert or not. The question was whether a metal does exist with the configuration $d^{10} s^2 p^6$. – Maurice Jan 13 at 10:18
• Wiki seems (?) to talk about a (n-1)d ns np configuration, that could have relation with closed shell and inert atom. The examples on this answer seems to be about "(n-1)p (n-1)d ns" – pasaba por aqui Jan 13 at 19:07