I'm building a dehumidifier based on $\ce{CaCl2}$-solution as descant, which is to be regenerated by heating and evaporation.
I thought it would be a good idea to add some citric acid to combat chalk-buildup due to rather hard tap water.
To test for possible reactions of $\ce{CaCl2}$ and citric acid, I mixed a 30% $\ce{CaCl2}$ solution by weight, added different amounts of acid (10%, "rather more", "very much") and boiled them. (My main fear being that some Ca might react with Citric acid to form a precipitate, which did NOT happen.) While heating, the solutions with more citric acid turned dark turquoise, but remained clear. Using vinegar did not cause a color-change. Heating $\ce{CaCl2}$ or citric acid alone does not cause color change. No other reactants (I know of) were present. It seems that cooking for longer turns the solution darker, but I may be mistaken on that.
The reactions I could think of should all be colorless/white, not blue/green/turquoise: Ca-citrate, decomosed citric acid, I didn't find sources for citric $\ce{Ca}$ complexes. Maybe a $\ce{Cl}$-complex is formed, but $\ce{Ca}$ is the only available metal, and again I couldn't find resources for chlorine $\ce{Ca}$ complexes. Impurities are probably not at fault, since the color is very strong/dark.
What I'm asking is specifically what reactions might occur between $\ce{CaCl2}$ and citric acid. I know of enough ways to get around my hard-water problem.
Edit:
The pot I used for heating was at fault. Heating in an enamel pot showed no color change. Thanks @poutnik and @m-farooq
I would still be very curious as to what reaction might cause a green/blue color change. From what I can tell, the metal pot is made of stainless steel.