# Particules speed in ideal gasses [closed]

According to Graham's law, we can calculate de average speed of gasses by using the formula

$$v^2=\frac{3RT}{M}$$

I tried to use this simulation and got these data by keeping same particles amount and increasing the temperature(average speed(m/s) - temperatura(°C)):

T in C V in m/s
27 454
50 480
90 510
130 530
225 590
350 660
425 710
500 740

But, shouldn't be the speed ($$v$$) a square function of the temperature? ($$T=\frac{Mv^2}{3R}$$ ) What am I doing wrong?

• The shoe is on the other foot (the square is on the other quantity), and you should use the Kelvin scale. Using the Celsius scale, RT will not be proportional to the kinetic energy of particles (just try below freezing to convince yourself). Dec 26 '20 at 16:12
• You are confused about the equations. Your first equation is a function of temperature and the second is a function of v squared.
– LDC3
Jan 3 at 0:33

T in K $$V^2$$ in $$\pu{m2 s-2}$$