1
$\begingroup$

Say we've a cubic crystal of unity edge length.

A set of planes in such a crystal is specified by their miller indice as $(3 2 0)$. One of these planes then has intercepts on the axes as $(2 ,3 ,\infty)$. It's well known that the interplanar distance between two adjacent planes in a cubic lattice is given

$d_{hkl} = \frac{a}{\sqrt{h^2+k^2+l^2}}$,in our case this gives us

$d_{320} = 1/\sqrt13$.

Now if I look at the planes which form the Miller indices of $ 3 2 0$ I find that apart from a plane having intercepts as $(2 ,3,0)$ an adjacent parallel plane to this plane having the same indices will pass via origin $0,0,0$ and the distance between them is $d_{320} = 6/\sqrt13$

Which contradicts the above result! Can anyone please point out what's wrong in my reasoning?

$\endgroup$
0
3
$\begingroup$

Your adjacent plane isn't. miller indices

Worth a thousand words, they say.

$\endgroup$
1
  • $\begingroup$ Thank you Mr Ivan Neretin. $\endgroup$ – Kashmiri Nov 28 '20 at 3:58

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.