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Inside the container is cold water and outside the container is hot water. B is the microscopic view of container walls .W is water And A is hot water.

What I have shown is the microscopic view of container walls(Small part )

A is the surrounding and B is the microscopic view of the walls of container ( Since there is some thickness of container walls and we can say that there are molecules present there ).

As you can see , when cold water molecules apply force on B (walls of container at left side) , B walls also apply force on water molecules and same has happened in the part where there is hot water.This is from the Newton’s third law of motion.

Average Kinetic Energy of water molecules will be less since it is cold water.So less force applied by water molecules on the wall.

Average kinetic energy of hot water will be more than cold water.So it applies more force on walls of container than by cold water.

I hope I have written the things clear till here.

Q1 Is it that the walls container will be pushed by B towards right side and not left side ? Because there is more force by Hot water and not cold water.

Q2 Does heat get transferred here because the Average kinetic Energy of the walls of container will increase due to force of A on B? And those will put the molecules inside B into motion which will further put water molecules into movement and therefore making heat transfer ?

Q3 Does heat transfer happen only because of this displacement?

HAVE I WRITTEN THE MEHTOD OF HEAT TRANSFER?IF NOT, THEN PLEASE HELP IN CORRECTING ME.

I am trying to make my self understand heat transfer in details. Please tell if how can I improve the quality of my question if not good.

enter image description here

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    $\begingroup$ Using photos/screenshots of ( even handwritten) text instead of typed text itself is strongly discouraged. It is impossible to index/search/reuse it in answers referring to it. In a case of handwritten text, it puts extra burden on responders to properly decipher it. That all may lead to the question being ignored or even closed. Consider copy/paste or retyping and using eventually MathJax for expressions and formulas. $\endgroup$
    – Poutnik
    Nov 16 '20 at 19:25
  • $\begingroup$ Ok.I have described everything above needed.Only diagram is needed to see that’s why I put this $\endgroup$
    – srijan Sri
    Nov 16 '20 at 19:26
  • $\begingroup$ I have edited it and made the text gone. $\endgroup$
    – srijan Sri
    Nov 16 '20 at 19:27
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    $\begingroup$ You need to be more clear and specific when you explain the problem. That greatly helps yourself correctly understanding it. Example: "K.E of water will be less since it cold water" 1.) Spell out K.E. 2.) it's not kinetic energy, it is thermal energy, or average kinetic energy of water molecules 3.) that's not the conclusion you want to draw, but a prerequisite: not "will be less", but "is smaller" 4.) the second part has no verb, "it is cold water". All this might sound petty to you now, but it is crucial so the reader, including yourself, can concentrate on the issue. $\endgroup$
    – Karl
    Nov 16 '20 at 19:53
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    $\begingroup$ Forces are useful to explain the pressure. They are no use for explaining heat transfer. $\endgroup$
    – Maurice
    Nov 16 '20 at 20:23
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A1: There is no displacement of the wall, forces are in equilibrium with zero net force. There are initiated stronger vibrations on warmer wall side by energetic hot air molecules. And weaker vibrations on colder wall side by energy leaching cold water molecules .

A2a: If the wall initial temperature was the cold water temperature, then yes. Otherwise no, as the mean kinetic energy of wall molecules can generally goes both ways, depending on initial temperatures of air, wall and water, weighted by air and water thermal capacity a conductivity.

A2b: Yes

A3: No, as there is no displacement. Hot air with in average more energetic molecules causes stronger vibrations of wall molecules, which cause faster motion of water molecules.

Imagine the whole scenario in more familiar macro world. 2 boxes of ideally elastic balls in gravityless ISS station, separated by a wall of balls interconnected by elastic strings holding all of them at their place. Now, balls in one of boxes move faster. What will happen during the time ?


The mean Kinetic energy of molecules is proportional to absolute temperature. Their mean speed is then proportional to the square root of absolute temperature and momentum to the absolute temperature.

Pressure on the walls is proportional to momentum change rate, what is proportional to molecule momentum and the rate of collisions. For gases in constant volume, both is proportional to square root of absolute temperature, so pressure is proportional to absolute temperature of ( ideal ) gas.

But pressure is not essential for molecular mechanism of heat transfer.

Molecules of matter at given temperature do not have the same speed and kinetic energy. During their collisions, it fluctuates all the time. What is constant is their mean value.

For monoatomic ideal gas, the mean kinetic energy of 1 mole of the gas is $E_\mathrm{k}=3/2RT$, where R is the universal gas constant about 8.314 J/K/mol. The speed distribution follows the Maxwell-Boltzmann distribution.

It means that for given kinetic energy and speed of a molecule, we cannot say what is the temperature of matter the molecule belongs.

When 2 different regions of matter have different temperature, they exchange heat, what means molecular kinetic energy.

Molecules from adjacent regions mutually exchange kinetic energy by random way by collisions. As by random collisions, they can both gain or lose the energy.

Molecules from both colder and warmer regions mutually both transfer and accept the energy. If temperatures are equal, their mean kinetic energy (*) is equal and the rates of energy flow are equal in both directions. If one region is warmer, the rate of passing energy is greater than the rate of accepting energy.


(*) It is more complicated, as more exactly, it means the mean kinetic energy per each way the molecule can move, called degree of freedom. But the above is still valid for monoatomic gases.

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  • $\begingroup$ Do you mean to say what I have written is right or wrong @Poutnik.You have told the bit same thing but I don’t know what are you trying to say from my question.If you can also give a diagram.It will be really helpful. $\endgroup$
    – srijan Sri
    Nov 17 '20 at 9:04
  • $\begingroup$ I do appreciate your efforts.That coordination with my question.Telling me where am I exactly wrong from the lines would help a lot to understood this concept. $\endgroup$
    – srijan Sri
    Nov 17 '20 at 9:08
  • $\begingroup$ Ok Thank you so much.I will keep it in mind. $\endgroup$
    – srijan Sri
    Nov 17 '20 at 10:55
  • $\begingroup$ For atoms , displacement is not necessary but vibration can also happen instead of displacement of walls. $\endgroup$
    – srijan Sri
    Nov 17 '20 at 10:57
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    $\begingroup$ Yes, as written. $\endgroup$
    – Poutnik
    Nov 17 '20 at 10:59

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