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I read that chlorine is more reactive than oxygen (despite being less electronegative). Then,

How is this displacement reaction occurring? $$\ce{CuO(s) + 2 HCl(aq) -> CuCl2(aq) + H2O(l)}$$

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In most of the displacement reactions that I've seen, the most reactive elements pair up:

$\ce{FeS + HCl -> FeCl2 + H2S}$ $\ce{(Fe>H, Cl>S)}$

$\ce{PbO + 2HNO3 -> Pb(NO3)2 + H2O}$ $\ce{(Pb>H, NO3>O)}$

$\ce{2NaOH + H2SO4 -> Na2SO4 + 2H2O}$ $\ce{(Na>H, SO4>OH)}$

$\ce{Na2SO4 + BaCl -> BaSO4 + NaCl}$ $\ce{(Ba>Na, SO4>Cl)}$

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    $\begingroup$ "More reactive" is not a thing at all. The displacement has nothing to do with reactivity (which itself, I repeat, is not a thing at all). Basic oxides tend to react with acids; that's it. $\endgroup$ – Ivan Neretin Nov 12 '20 at 11:33
  • $\begingroup$ @IvanNeretin So, how do you decide which way will this reaction go? Na₂SO₄ + BaCl₂ → BaSO₄ + NaCl BaSO₄ + NaCl → Na₂SO₄ + BaCl₂ $\endgroup$ – Shub Nov 12 '20 at 11:56
  • $\begingroup$ Strongly related (the mentioned reaction is discussed): chemistry.stackexchange.com/questions/126150/… $\endgroup$ – Nilay Ghosh Nov 12 '20 at 12:08
  • $\begingroup$ @Shub This I decide based on solubility. $\endgroup$ – Ivan Neretin Nov 12 '20 at 12:23
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    $\begingroup$ Note the Chemistry site prefers plain text titles for indexing/searching reasons. $\endgroup$ – Poutnik Nov 15 '20 at 9:39

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