I've studied that when 1,3-dibromopropane (or in general any halogen, not just bromine) is heated with Zn dust, the electrons produced cause the halogens to break away homolytically and two free radicals are formed. These free radicals then combine to form cyclopropane.
My question is, will this also occur for 1,3-dihalides when the carbon count is increased, say in 1,3-dibromobutane?
Everything I found related to this was either talking about the 3-carbon dihaloalkane case, or seemed to be some complicated free radical cyclization which was way out of my reach.
mhchem
package as this provides convenient and correct typography, i.e.$\ce{H2O}$
$\ce{H2O}$ not$H2O$
$H2O$. $\endgroup$ – orthocresol♦ Oct 14 '20 at 10:41