I came through this question: Which form is stable Gauche or Anti in F-CH2-CH2-F? My answer: Due to lone pair repulsion Anti form should be more stable but the answer is given Gauche form. Please tell me how is gauche form more stable in this case?
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1$\begingroup$ in gauche form there is intramolecular hydrogen bonding between H and F which makes it stable... $\endgroup$– maverickOct 3, 2020 at 13:58