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I came through this question: Which form is stable Gauche or Anti in F-CH2-CH2-F? My answer: Due to lone pair repulsion Anti form should be more stable but the answer is given Gauche form. Please tell me how is gauche form more stable in this case?

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    $\begingroup$ in gauche form there is intramolecular hydrogen bonding between H and F which makes it stable... $\endgroup$ – maverick Oct 3 '20 at 13:58
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This problem should be referred to concept called stereoelectronic effect. It is stabilized by the donation of $\sigma_{C-H}$ bond to $\sigma_{C-F}$ bond, leading to decrease energy of the whole system.enter image description here

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