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What is the equation to represent the polymerization of propene?

It has to be in the form of general formula:

$$\ce{H-R-OH + H-R-OH -> H-R-R-OH + H2O}$$

I have this so far: $$\ce{CH3-CH=CH2-OH + CH3-CH=CH2-OH -> ... + H2O}$$

I'm confused as to how this reaction would work.

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    $\begingroup$ What do either of your equations have to do with propene? $\endgroup$ – user55119 Oct 2 '20 at 2:07
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    $\begingroup$ 4 bonds of a carbon atom should be enough, don't you think ? BTW, others are confused as well, as propene polymerization does not work this way. It is not polycondensation. $\endgroup$ – Poutnik Oct 2 '20 at 4:57
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    $\begingroup$ The enol form of propaldehyde .... no, you gone up to a very wrong start. Grab your textbook, and try again after reading it once more! $\endgroup$ – Karl Oct 2 '20 at 6:48
  • $\begingroup$ Propene condenses to give Polypropylene, but your question body asks something very different from the title... $\endgroup$ – Aniruddha Deb Oct 2 '20 at 8:49
  • $\begingroup$ @AniruddhaDeb Propene polymerizes to PP, (poly)condensation assumes elimination of small molecules like water. $\endgroup$ – Poutnik Oct 2 '20 at 9:36
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Propene performs radical ( denoted by $\cdot$ ) driven polymerization:

$$\ce{R. + CH2=CH(CH3) -> R-CH2-CH(CH3).}$$

where the radical end is eventually terminated by recombination,stopping the polymerization. Polymerizations typically convert a double bond of a monomer to a single bond, freeing extra electrons to create extra bonds between monomers.

OTOH, polycondensation eliminates small molecules like water from atoms of bonding functional groups, like :

Polyethylene terephthalate ( PET ) production eliminates water molecules :

$$\ce{R-COOH + HO-CH2-CH2-OH + HOOC-C6H4-COOH \\-> R-CO-O-CH2-CH2-O-CO-C6H4-COOH + 2 H2O}$$

Similarly polycarbonate eliminate hydrogen chloride ( that is immediately neutralized by hydroxide):

$$\ce{R-OH + COCl2 + HO-dian-OH ->[NaOH] R-O-CO-O-dian-OH + 2 HCl}$$

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