# Major product of Crossed-Cannizzaro Reaction between benzaldehyde and formaldehyde [duplicate]

I came across a question:

Predict the major product when conc. $$\ce{NaOH}$$ is added to a mixture of $$\ce{PhCHO}$$ and $$\ce{HCHO}$$.

According to me, as $$\ce{HCHO}$$ is less hindered and $$\ce{>C=O}$$ of $$\ce{HCHO}$$ is more reactive, so the major products must be $$\ce{CH3ONa}$$ and $$\ce{HCOONa}$$. The hydride transfer should be from one Formaldehyde molecule to the other.

However, the answer was given as $$\ce{HCOONa}$$ and $$\ce{PhCH2ONa}$$. Is there a mistake on my part?

• Rate determining step of Cannizaro is the hydride transfer and not nucleophilic attack – Safdar Sep 24 '20 at 12:59
• Why would the hydride prefer transferring to the PHCHO? – Soumyadwip Chanda Sep 24 '20 at 13:06
• So what happens to the benzaldehyde> – Safdar Sep 24 '20 at 13:18
• See this earlier Q&A. – ron Sep 24 '20 at 13:39
• Effectiively there is no free formaldehyde to accept hydride. – user55119 Sep 24 '20 at 14:45