Following up the question Formation of a stable hydrate. I understand that for cyclopropanone the change in hybridization is the reason for stabilization of hydrate since it relieves the angle strain.
So, can this be further be given as a reason to state the hydrate of 2‐indanone (structure below) will be stable? I suppose upon hydration the angle will change from 120° to 109.8°, bringing the angle closer to that of a pentagon that is 108°.
I am confused if this is appropriate or if it's true. If it's wrong, please explain.
P.S. After going through the comments I understood by considering keto-enol tautomerisation that hydration might not at all be favourable.