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In order to remove temporary hardness of water, it is boiled.

On boiling, while Ca(HCO3)2 gives CaCo3(ppt.) , Mg(HCO3)2 gives Mg(OH)2(ppt.).

According to my book precipitation of Mg(OH)2 occurs due to it's high solubility product.

But doesn't a higher solubility product mean a higher solubility? (Since solubility product is the product of solubilities of each component)

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    $\begingroup$ Can you provide the exact full quote from the book? $\endgroup$
    – Andrew
    Sep 4 '20 at 11:27
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    $\begingroup$ it should be lower solubility product. $\endgroup$ Sep 4 '20 at 11:36
  • $\begingroup$ Is it an error in the book? $\endgroup$
    – JKR
    Sep 4 '20 at 12:05
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    $\begingroup$ Yes. it is a mistake. $\endgroup$
    – Maurice
    Sep 4 '20 at 13:35

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