# Oxidation of Unsymmetrical Ketones using Selenium Dioxide

I have searched the whole internet but I could only see examples where the authors of the article took $$\ce{R1}$$ and $$\ce{R2}$$ as the alkyl groups around the carbon.
This is regarding the oxidation of carbonyl compounds (I am specifically searching about ketones) using $$\ce{SeO2}$$.
What I understood was $$\ce{C=O}$$ got introduced on the alpha-carbon and two hydrogens from that carbon were lost.
I would like to know the product obtained on reacting pentan-2-one with $$\ce{SeO2}$$. Will the carbon having 3 alpha-hydrogens become $$\ce{C=O}$$ or will the other one having 2 alpha hydrogens become $$\ce{C=O}$$?

References:

1. Selenium dioxide oxidation of ketones and aldehydes. Evidence for the intermediacy of .beta.-ketoseleninic, K. Barry Sharpless and Kenneth M. Gordon Journal of the American Chemical Society, 1976, 98 (1), 300-301 DOI: 10.1021/ja00417a083