While teaching me magnetism, my teacher told me about the spin of an electron. He told me that the spin of .5 means that if we rotate the electron twice counter-clockwise on its axis, we would have the same face(picture) of the electron. And if we rotate an electron of -0.5 spin twice in the opposite direction, we would have the same face. But if rotate it only once(360⁰), we would not get the same face/picture of an electron.

How can this be possible? Or am I just making a mistake somewhere? A simple explanation would be greatly appreciated for I am only a tenth grader.

  • $\begingroup$ In my understanding, the wavefunction of fermion particles like electrons is not identical wrt 360 degree rotation, but has the opposite value. Superposition of these 2 values has the zero norm, leading to zero probability. It then leads to zero probability 2 fermions can share the identical quantum state. But I am very far from quantum mechanic expert, so so I cannot provide detailed reasoning. $\endgroup$
    – Poutnik
    Aug 25, 2020 at 8:04
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    $\begingroup$ A general hint: Do not try to force classical mechanics pictures on quantum mechanics. Sometime this may work, but often not and only lead to wrong ideas. Quantum mechanics is very different and unintuitive at first. $\endgroup$
    – Feodoran
    Aug 25, 2020 at 8:15
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    $\begingroup$ To complement Feodoran, for the given value of the electron mass and maximal possible electron radius limit, there is no classical way how an electron could have such a high value of the spin angular momentum, so the classical idea of a fast spinning ball cannot be applied. $\endgroup$
    – Poutnik
    Aug 25, 2020 at 8:24
  • $\begingroup$ The particular value $\pm 0.5$ means the multiplier of the Planck constant $\hbar$, providing the value of the preferred axis projection of the electron spin angular momentum $\pm 0.5 \cdot \hbar$. ( Note that $\hbar = \frac{h}{2 \pi} $) $\endgroup$
    – Poutnik
    Aug 25, 2020 at 8:48
  • $\begingroup$ See youtube.com/watch?v=cd2Ua9dKEl8 and youtube.com/watch?v=z_6B2M12H9w . A potentially relevant example of how 2 pi rotation is not enough but 4 pi can be : youtube.com/watch?v=Nat-EsReXtQ . $\endgroup$ Aug 25, 2020 at 20:26

2 Answers 2


It is very tempting (and often also very useful!) to picture electron spin as an angular momentum vector, similar to a spinning top. Using this analogy, there are two properties (or numbers) of this angular momentum vector that we need in order to describe the electron spin. The first one is the spin itself and this is often designated the symbol $s$. The second number is the projection of the spin on a particular axis (often the $z$ axis) and this is assigned the symbol $m_s$.

You probably learned already that not all values of $s$ and $m_s$ are allowed in quantum mechanics. From measurements we know that an electron has a spin of $s=1/2$ (always positive) and its projections can be $m_s=+1/2$ or $m_s=-1/2$. The quantum numbers $s$ and $m_s$ are just numbers we use to label a particular state of the electron, but when we do measurements we also measure units. The units of angular momentum are J s (Joule second) and from comparing the classical definition of angular momentum with the rules of quantum mechanics, we can derive that one unit of angular momentum in quantum mechanics has a value of $\hbar$. This means that the angular momentum of the electron has a value which is basically half of what you would expect based on classical arguments and sometimes people like to emphasize the weirdness of this by saying things like "an electron has to rotate twice around its axis to come back to its original position". Of course this not true because the angular momentum of the electron is not a consequence of a rotation at all (the electron is a point particle). In addition, the sign of the projection of $s$ has nothing to do with this hypothetical rotation either. The sign of $m_s$ does influence the interaction of the electron with an inhomogenous magnetic field. If you have a magnetic field gradient along the $z$ direction, electrons in one state move up while electrons in the other state move down and you will see two separated spots on a position sensitive detector behind the magnet. This is the basis of the famous Stern-Gerlach experiment. Note that you have to perform these kind of experiments with neutral systems that behave like a single electron because a charged electron would experience a much stronger interaction between its charge and the magnetic field (Lorentz force) than between its spin and the magnetic field (Zeeman interaction).

What I find very interesting about half-integer spin is that there is no orientation possible for which the electron spin does not interact with the magnetic field (which would correspond to $m_s=0$ or a perpendicular orientation of the electron spin with respect to the magnetic field).

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    $\begingroup$ rather spin number $s=1/2$ versus spin itself $ \hbar \sqrt{s(s+1)} = \hbar \left(\sqrt{sqrt(3)/2}\right) \simeq 0.866 \hbar$, where those $\pm 0.5 \hbar$ are the projection of $0.866 \hbar$ along the preferred axis. $\endgroup$
    – Poutnik
    Aug 25, 2020 at 12:12
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    $\begingroup$ In a way the electron does have to "rotate" through 720° to "get back to original", because a "rotation" through 360° converts the spin wavefunction to the negative of itself ($\exp(\mathrm{i}2\pi\hat{S}_z)|\alpha\rangle = -|\alpha\rangle$, $\exp(\mathrm{i}2\pi\hat{S}_z)|\beta\rangle = -|\beta\rangle$, something to do with spinors...? I know very little...). But I am not really convinced that that is what OP's teacher means... $\endgroup$ Aug 25, 2020 at 12:27
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    $\begingroup$ @orthocresol You are correct of course that the $\hat{S}_z$ is the generator of rotation, although it does not really corresponds to a physical rotation of the electron itself. There is certainly a lot more to the interpretation of spin that I did not address here. $\endgroup$
    – Paul
    Aug 25, 2020 at 12:36
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    $\begingroup$ To stress that spin is not really a rotation, maybe a note on where this spin = rotation analogy is coming from might be helpful. AFAIK this ONLY because the mathematical description of spin (the operators and their commutators) is very similar to angular momentum. $\endgroup$
    – Feodoran
    Aug 25, 2020 at 18:29
  • $\begingroup$ the electron is a point particle Wellll..... not in an orbital it isn't. $\endgroup$
    – J...
    Aug 25, 2020 at 21:57

The strange properties of half-integer spin are one of those mysterious facts that make physics interesting. It's part of the geometry of a mathematical object called a 'spinor'. The name comes from making an analogy with a 'vector', but related to spin.

Spinors are fairly advanced mathematics, but there is an intuitive way to think about them that works a lot of the time. A spinor can be thought of as an ordered pair of oriented reflecting planes passing through a point. 'Ordered' means that we distinguish the first and second plane. 'Oriented' means they have a front and a back face. If you do two reflections one after the other, you get a rotation, so any spinor has a rotation associated with it.

Now if the two planes are identical and facing the same way, the first and second reflection reverse one another, and you get the identity. As you twist one of the planes with respect to the other, the corresponding rotation is through twice the angle between the intersecting planes, about an axis along the line where the two planes meet. When the planes get to 45 degrees apart, they produce a 90 degree rotation. When they get to 90 degrees apart they produce a 180 degree rotation. When they are 135 degrees apart the result is a 270 degree rotation. And when the planes are 180 degrees apart, so they are lined up back-to-back, you get a 360 degree rotation. Note that because the planes have a well-defined front and back, two planes back-to-back are the opposite of two planes facing the same way.

The distinction is invisible if all you can see is the rotation that results, but the physics of electrons can tell the difference between planes back-to-back or facing the same way.

If you keep on rotating one plane with respect to the other, when the first plane has turned 360 degrees and is back to where it started, the rotation produced by the pair of reflections has turned a full 720 degrees. This is what is meant by saying you have to rotate a spinor 720 degrees to get back to where you started. It's the rotation represented by the pair of planes that is being spun.

I should say, the above picture is not quite right. The spinor is really representing some kind of oriented angle in space. It's the intersection axis and the angle between the planes that matters, not the particular planes themselves. So if you rotate both of the planes together about their common axis (rather than just rotating one with respect to the other) you get the same spinor. Similarly, any pair of perfectly aligned planes is the identity and always the same, and any pair of perfectly opposed planes is its negative. I realise that's probably somewhat unclear - it's hard to give an intuitive geometric picture of a very unfamiliar concept.

Now I'm going to get more technical, for anyone who wants to look into it more deeply. There is an extension to the geometry of vectors called 'geometric algebra', which was originally discovered by the English mathematician William Kingdon Clifford back in the days when they were inventing vector geometry. Clifford's geometric algebra was actually invented before vectors were fully developed and accepted, but vectors took over and Clifford's ideas were abandoned and forgotten in physics for a long time.

Geometric algebra has several different sorts of object in it, and unifies them all into a single structure. Scalars, which have no direction or extent; vectors, which represent a one-dimensional extent, a line, a directed length, or a reflection; bivectors, which represent a two-dimensional extent, a plane, a directed angle, or a rotation; and trivectors which represent a three-dimensional extent, or a volume. Scalars, vectors, bivectors, and trivectors can all be added and multiplied together freely, so you can add a vector to a scalar and then multiply the result by a bivector and so on.

The 'spinors' in any space are 'the even sub-algebra' of the geometric algebra: the elements made up entirely of even-dimensional components. So in 3D space, as described above, this consists of just the scalars (0-dimensional) and bivectors (2-dimensional) and linear combinations of those. And in 3D this happens to be the space of products produced by multiplying two vectors together, each vector representing a reflection. When you multiply vectors in geometric algebra, you get the sum of a scalar (the dot product) and a bivector (closely related to the cross product) that describe how the vectors are oriented with respect to each other.

In 3D, the spinors (scalars + bivectors) also happen to be the same as the 'quaternions', which you may also have heard of. In 4D and higher, things get more complicated.

Geometric algebra gives a much more intuitive, 'geometric' picture of spinors, which otherwise are just mysterious abstract entities that you have to take on trust without ever really understanding them, which is what most physicists do.


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