Is this buffer possible?

Question

Can a buffer solution be obtained by mixing-

A) $$\ce{NH4Cl}$$ + $$\ce{CH3COONa}$$

B) $$\ce{CH3COOH}$$ + $$\ce{NH4OH}$$

My Thoughts

I know that a buffer solution can be obtained if we mix a acid and its salt of conjugate base or a base and its salt of conjugate acid.

But I was wondering whether a buffer solution can be prepared if we mix a weak acid and weak base or if we mix an acidic salt and basic salt?

• To be precise, $\ce{NH4Cl}$ and $\ce{CH3COONa}$ are solids and $\ce{NH4OH}$ doesn't exist.
– user7951
Aug 18 '20 at 18:33
• I meant there aqueous solutions. And you can assume $\ce{NH4OH}$ to be $\ce{NH3}$ dissolved in water. Aug 18 '20 at 18:55
• Not really. NH4OH is kind of an immortal myth. Aug 18 '20 at 19:12

Both cases are equivalent in the case of molar ratio 1:1. It would lead to a double buffer of $$\ce{HAc/Ac-}$$ and $$\ce{NH4+/NH3}$$. But the buffer capacity would be inferior, as the resulting $$\mathrm{pH}$$ is too far from the both respective $$\mathrm{p}K_\mathrm{a}$$.