1
$\begingroup$

When you are up in the air, the air pressure decreases and the altitude increases. What gas law is involved in the situation wherein your ears "pop" because of the difference in pressure.

$\endgroup$
  • 1
    $\begingroup$ Related: physics.stackexchange.com/questions/187905/why-do-our-ears-pop $\endgroup$ – Nilay Ghosh Aug 18 at 14:33
  • $\begingroup$ I’m voting to close this question because it's off topic. Physics at best, definitely no chemitry. $\endgroup$ – Karl Aug 18 at 17:05
  • 1
    $\begingroup$ @Karl to be fair, such things are discussed in any introductory chemistry text. $\endgroup$ – electronpusher Aug 18 at 19:45
  • $\begingroup$ Karl, I think you will agree that there is no distinct boundary between chemistry and physics. $\endgroup$ – M. Farooq Aug 19 at 0:12
2
$\begingroup$

The temperature and the volume of the inner ear are constant. When your ears pop during descent, air from the cabin goes into the ear, increasing the pressure. The law is the following:

$$n / P = const$$

You can derive this from the ideal gas law. It has no special name.

| improve this answer | |
$\endgroup$

Not the answer you're looking for? Browse other questions tagged or ask your own question.