# In Na extraction, is Ca2+ of CaCl2 reduced in addition to Na+ of NaCl in electrolysis

In Na extraction from $$\ce{NaCl}$$, $$\ce{CaCl2}$$ is added in electrolysis to lower the melting point of the mixture to about $$\pu{750 ^\circ C}$$. But doesn't $$\ce{Ca^2+}$$ cation compete with the $$\ce{Na+}$$ ion to be reduced at the cathode? If so, since $$\ce{Ca^2+}$$ is right next to the electrochemical series, should we not have a considerable amount of $$\ce{Ca}$$ as impurity in the $$\ce{Na}$$ that we have extracted? Where do the inconsistencies lie?

• Electrochemical series is for aqueous solution only! Aug 13 '20 at 22:27
• @Mithoron, Got it, thanks. But in this case, how will one decide which cation will be reduced without the help of the electrochemical series? Aug 13 '20 at 22:50
• Well, there are data for various solvents and melts, not nearly as commonly found or thorough, though. Aug 13 '20 at 22:54