What molecule results from treating 4-oxopentanal with $\ce{NH4Cl}$ and $\ce{NaCNBH3}$? Why? Is this a good, high yield reaction?

I believe that pyrrolidine is formed because amination will convert one carbonyl to an amine that reacts with the other carbonyl. However, I am unsure how reasonable this is and I'm unsure what happens to the original carbonyl oxygen.

New contributor
DadDad is a new contributor to this site. Take care in asking for clarification, commenting, and answering. Check out our Code of Conduct.
  • 1
    $\begingroup$ Reductive amination is OK. Succindialdehyde is harder to come by than pyrrolidine. $\endgroup$ – user55119 Jul 31 at 2:17
  • $\begingroup$ The carbonyl oxygens are lost as water during imine formation $\endgroup$ – Waylander Jul 31 at 5:48

Your Answer

DadDad is a new contributor. Be nice, and check out our Code of Conduct.

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.