# Synthesis question: Using reductive amination to form pyrrolidine

What molecule results from treating 4-oxopentanal with $$\ce{NH4Cl}$$ and $$\ce{NaCNBH3}$$? Why? Is this a good, high yield reaction?

I believe that pyrrolidine is formed because amination will convert one carbonyl to an amine that reacts with the other carbonyl. However, I am unsure how reasonable this is and I'm unsure what happens to the original carbonyl oxygen.

New contributor
DadDad is a new contributor to this site. Take care in asking for clarification, commenting, and answering. Check out our Code of Conduct.
• Reductive amination is OK. Succindialdehyde is harder to come by than pyrrolidine. – user55119 Jul 31 at 2:17
• The carbonyl oxygens are lost as water during imine formation – Waylander Jul 31 at 5:48