# Stability of radicals

I recently came across a question about the stability of radicals and this option was given as correct.

• $$\ce {F2C^.H}>\ce {C^.H3}$$

And the solution was given that $$\ce{FC^.H2}$$ and $$\ce{F2CH^.}$$ are more stable than $$\ce {C^.H3}$$ but $$\ce{C^.F3}$$ is less stable. Can anyone explain why?
If it has got something to do with inductive effect then all three $$\ce {F2C^.H},\ce{FC^.H2},\ce{C^.F3}$$ should be less stable than $$\ce {C^.H3}$$. Right?

• you might also want to consider lone pair repulsion between F atoms. – Safdar Faisal Jul 15 '20 at 13:15
• chemistry.stackexchange.com/questions/49754/… – Mithoron Jul 15 '20 at 15:36
• @RahulVerma Do you have anything to back up that claim? Normal radicals are electron-deficient. – Zhe Jul 16 '20 at 17:11
• @Zhe: No. I don't have. As the claim was wrong. – Rahul Verma Jul 17 '20 at 4:32